Problem 36 worked answer

The Orbit of i

Designed for Grade 10 Β· Grade 11 Β· Uses HS A2 math Β· About 11–28 minutes

Complete to collectSmoky Quartz PointLevel 2

At a glance

For , the orbit is

The values and repeat in a two-point cycle. Their distances from 0 are and , both at most 2, so the orbit stays bounded and belongs to the Mandelbrot set.

Key idea

Once an iteration returns to a value it has already reached, the deterministic next-step rule forces the entire future to repeat. A short, exact cycle can therefore certify infinitely many later steps.

Worked solution, part by part

1. Calculate and plot the orbit

Starting from :

point
0
1
2
3
4

The distinct plotted points are , , , and .

2. Identify the cycle

The value repeats . Since the same rule is applied each time, the value after it must again be , followed by . Therefore

3. Check the distances

For the two cycle values,

Both are at most 2. The earlier points and also have distance at most 2. Because every later point is one of the two cycle values, no point can escape; by the rule supplied on the worksheet, is in the Mandelbrot set.

Proof of boundedness

The table checks every value before the first repeat. The equal values force the following values to repeat in the same order, so the two checked cycle magnitudes account for every later iterate rather than only a finite sample.

Check

Substituting either cycle value confirms the arrows both ways: and . This makes the boundedness argument depend on an exact repeat, not on a picture that merely looks stable.

Technical fit and rating

MJ HS:A2.2 Β· C2 Β· W2 Standard challenge Β· Moderate workload

Number and quantity

How the rating works β†’

Worksheet arc Β· Guided Practice Β· 2 of 5 on Complete arc

Edge of Escape

Open the complex-orbit branch by introducing complex arithmetic, magnitude, and a bounded repeating orbit.

Keep exploring

Keep exploring