Problem 36 worked answer
The Orbit of i
Designed for Grade 10 Β· Grade 11 Β· Uses HS A2 math Β· About 11β28 minutes
At a glance
For , the orbit is
The values and repeat in a two-point cycle. Their distances from 0 are and , both at most 2, so the orbit stays bounded and belongs to the Mandelbrot set.
Key idea
Once an iteration returns to a value it has already reached, the deterministic next-step rule forces the entire future to repeat. A short, exact cycle can therefore certify infinitely many later steps.
Worked solution, part by part
1. Calculate and plot the orbit
Starting from :
| point | ||
|---|---|---|
| 0 | ||
| 1 | ||
| 2 | ||
| 3 | ||
| 4 |
The distinct plotted points are , , , and .
2. Identify the cycle
The value repeats . Since the same rule is applied each time, the value after it must again be , followed by . Therefore
3. Check the distances
For the two cycle values,
Both are at most 2. The earlier points and also have distance at most 2. Because every later point is one of the two cycle values, no point can escape; by the rule supplied on the worksheet, is in the Mandelbrot set.
Proof of boundedness
The table checks every value before the first repeat. The equal values force the following values to repeat in the same order, so the two checked cycle magnitudes account for every later iterate rather than only a finite sample.
Check
Substituting either cycle value confirms the arrows both ways: and . This makes the boundedness argument depend on an exact repeat, not on a picture that merely looks stable.
Technical fit and rating
Number and quantity
How the rating works βWorksheet arc Β· Guided Practice Β· 2 of 5 on Complete arc
Edge of Escape
Open the complex-orbit branch by introducing complex arithmetic, magnitude, and a bounded repeating orbit.