Problem 2 worked answer
The Necklace Code
Designed for Grade 3 · Uses Late Grade 3 math · About 2–6 minutes
At a glance
- Part 1: Position 19 contains a sapphire.
- Part 2: The necklace contains 5 rubies, 10 sapphires, and 4 emeralds.
Key idea
The four-jewel pattern is ruby, sapphire, sapphire, emerald. Instead of drawing all 19 jewels, separate 19 into complete groups of 4 and the jewels left over.
This means the necklace contains 4 complete pattern groups followed by the first 3 jewels of the next group.
1. Identify position 19
The 4 complete groups fill positions 1 through 16. Positions 17, 18, and 19 restart the pattern:
- Position 17 is ruby.
- Position 18 is sapphire.
- Position 19 is sapphire.
Therefore position 19 contains a sapphire.
2. Count each jewel type
One complete group contains 1 ruby, 2 sapphires, and 1 emerald. Four complete groups contain:
- rubies;
- sapphires; and
- emeralds.
The final three jewels are ruby, sapphire, sapphire. Adding those gives 5 rubies, 10 sapphires, and 4 emeralds.
Check
The three counts must total the 19 positions: . Position 19 is also the third position in its four-jewel group, and the third jewel of the pattern is sapphire.
Technical fit and rating
Patterns and algebra
How the rating works →mathjewels.com/answers/problems/2/