Problem 2 worked answer

The Necklace Code

Designed for Grade 3 · Uses Late Grade 3 math · About 2–6 minutes

Earn one jewelGreen TourmalineLevel 2

At a glance

  • Part 1: Position 19 contains a sapphire.
  • Part 2: The necklace contains 5 rubies, 10 sapphires, and 4 emeralds.

Key idea

The four-jewel pattern is ruby, sapphire, sapphire, emerald. Instead of drawing all 19 jewels, separate 19 into complete groups of 4 and the jewels left over.

This means the necklace contains 4 complete pattern groups followed by the first 3 jewels of the next group.

1. Identify position 19

The 4 complete groups fill positions 1 through 16. Positions 17, 18, and 19 restart the pattern:

  1. Position 17 is ruby.
  2. Position 18 is sapphire.
  3. Position 19 is sapphire.

Therefore position 19 contains a sapphire.

2. Count each jewel type

One complete group contains 1 ruby, 2 sapphires, and 1 emerald. Four complete groups contain:

  • rubies;
  • sapphires; and
  • emeralds.

The final three jewels are ruby, sapphire, sapphire. Adding those gives 5 rubies, 10 sapphires, and 4 emeralds.

Check

The three counts must total the 19 positions: . Position 19 is also the third position in its four-jewel group, and the third jewel of the pattern is sapphire.

Technical fit and rating

MJ 3.8 · C2 · W1 Standard challenge · Light workload

Patterns and algebra

How the rating works →

mathjewels.com/answers/problems/2/

Keep exploring

Keep exploring